1312010012213 has 4 divisors (see below), whose sum is σ = 1312014846240. Its totient is φ = 1312005178188.

The previous prime is 1312010012191. The next prime is 1312010012239. The reversal of 1312010012213 is 3122100102131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1312010012213 - 2¹⁰ = 1312010011189 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1312010012191 and 1312010012200.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1312010015213) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1984043 + ... + 2561336.

It is an arithmetic number, because the mean of its divisors is an integer number (328003711560).

Almost surely, 2^{1312010012213} is an apocalyptic number.

It is an amenable number.

1312010012213 is a deficient number, since it is larger than the sum of its proper divisors (4834027).

1312010012213 is an equidigital number, since it uses as much as digits as its factorization.

1312010012213 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4834026.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 1312010012213 its reverse (3122100102131), we get a palindrome (4434110114344).

The spelling of 1312010012213 in words is "one trillion, three hundred twelve billion, ten million, twelve thousand, two hundred thirteen".