Base | Representation |
---|---|
bin | 10011000101111001111… |
… | …001000000011000011111 |
3 | 11122102112020022021201111 |
4 | 103011321321000120133 |
5 | 132443444030342231 |
6 | 2442421251522451 |
7 | 163534555045234 |
oct | 23057171003037 |
9 | 4572466267644 |
10 | 1312010012191 |
11 | 4664694a20aa |
12 | 1923395b9427 |
13 | 96950356228 |
14 | 4770465178b |
15 | 241dd4c24b1 |
hex | 13179e4061f |
1312010012191 has 2 divisors, whose sum is σ = 1312010012192. Its totient is φ = 1312010012190.
The previous prime is 1312010012161. The next prime is 1312010012239. The reversal of 1312010012191 is 1912100102131.
It is a weak prime.
It is an emirp because it is prime and its reverse (1912100102131) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1312010012191 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1312010012111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656005006095 + 656005006096.
It is an arithmetic number, because the mean of its divisors is an integer number (656005006096).
Almost surely, 21312010012191 is an apocalyptic number.
1312010012191 is a deficient number, since it is larger than the sum of its proper divisors (1).
1312010012191 is an equidigital number, since it uses as much as digits as its factorization.
1312010012191 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108, while the sum is 22.
The spelling of 1312010012191 in words is "one trillion, three hundred twelve billion, ten million, twelve thousand, one hundred ninety-one".
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