13120110110147 has 2 divisors, whose sum is σ = 13120110110148. Its totient is φ = 13120110110146.

The previous prime is 13120110110137. The next prime is 13120110110249. The reversal of 13120110110147 is 74101101102131.

13120110110147 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is an emirp because it is prime and its reverse (74101101102131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13120110110147 - 2⁸ = 13120110109891 is a prime.

It is not a weakly prime, because it can be changed into another prime (13120110110137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6560055055073 + 6560055055074.

It is an arithmetic number, because the mean of its divisors is an integer number (6560055055074).

Almost surely, 2^{13120110110147} is an apocalyptic number.

13120110110147 is a deficient number, since it is larger than the sum of its proper divisors (1).

13120110110147 is an equidigital number, since it uses as much as digits as its factorization.

13120110110147 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 168, while the sum is 23.

Adding to 13120110110147 its reverse (74101101102131), we get a palindrome (87221211212278).

The spelling of 13120110110147 in words is "thirteen trillion, one hundred twenty billion, one hundred ten million, one hundred ten thousand, one hundred forty-seven".