Base | Representation |
---|---|
bin | 1011111011101100001110… |
… | …1111110001000110101010 |
3 | 1201110021022022120011002200 |
4 | 2332323003233301012222 |
5 | 3204424443213413002 |
6 | 43523144112441030 |
7 | 2522616442433334 |
oct | 276730357610652 |
9 | 51407268504080 |
10 | 13120114201002 |
11 | 41a9233475806 |
12 | 157a923849176 |
13 | 7422b5719033 |
14 | 3350345b8454 |
15 | 17b43e699b1c |
hex | beec3bf11aa |
13120114201002 has 48 divisors (see below), whose sum is σ = 28828488349440. Its totient is φ = 4311953100000.
The previous prime is 13120114200967. The next prime is 13120114201039. The reversal of 13120114201002 is 20010241102131.
13120114201002 is a `hidden beast` number, since 1 + 31 + 201 + 1 + 420 + 10 + 0 + 2 = 666.
It is a super-3 number, since 3×131201142010023 (a number of 40 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 14663374 + ... + 15532377.
It is an arithmetic number, because the mean of its divisors is an integer number (600593507280).
Almost surely, 213120114201002 is an apocalyptic number.
13120114201002 is an abundant number, since it is smaller than the sum of its proper divisors (15708374148438).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13120114201002 is a wasteful number, since it uses less digits than its factorization.
13120114201002 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 30196099 (or 30196096 counting only the distinct ones).
The product of its (nonzero) digits is 96, while the sum is 18.
Adding to 13120114201002 its reverse (20010241102131), we get a palindrome (33130355303133).
The spelling of 13120114201002 in words is "thirteen trillion, one hundred twenty billion, one hundred fourteen million, two hundred one thousand, two".
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