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131201142015001 is a prime number
BaseRepresentation
bin11101110101001110100101…
…011101101100010000011001
3122012112201002011121202211011
4131311032211131230100121
5114144044414323440001
61143012550023533521
736430653415320352
oct3565164535542031
9565481064552734
10131201142015001
1138894101296073
121286b7b0bba2a1
1358292a36415c6
142458252240d29
151027c99668d51
hex7753a576c419

131201142015001 has 2 divisors, whose sum is σ = 131201142015002. Its totient is φ = 131201142015000.

The previous prime is 131201142014959. The next prime is 131201142015037. The reversal of 131201142015001 is 100510241102131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 105857368267401 + 25343773747600 = 10288701^2 + 5034260^2 .

It is a cyclic number.

It is not a de Polignac number, because 131201142015001 - 227 = 131201007797273 is a prime.

It is not a weakly prime, because it can be changed into another prime (131201142016001) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65600571007500 + 65600571007501.

It is an arithmetic number, because the mean of its divisors is an integer number (65600571007501).

Almost surely, 2131201142015001 is an apocalyptic number.

It is an amenable number.

131201142015001 is a deficient number, since it is larger than the sum of its proper divisors (1).

131201142015001 is an equidigital number, since it uses as much as digits as its factorization.

131201142015001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 240, while the sum is 22.

Adding to 131201142015001 its reverse (100510241102131), we get a palindrome (231711383117132).

The spelling of 131201142015001 in words is "one hundred thirty-one trillion, two hundred one billion, one hundred forty-two million, fifteen thousand, one".