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13120120210122 = 23217194365518011
BaseRepresentation
bin1011111011101100010000…
…0110101100001011001010
31201110021022201212110001200
42332323010012230023022
53204430001233210442
643523144445325030
72522616544501542
oct276730406541312
951407281773050
1013120120210122
1141a92368aa522
12157a925866776
137422b6a41223
14335035300322
1517b43ee8534c
hexbeec41ac2ca

13120120210122 has 192 divisors, whose sum is σ = 32429078922240. Its totient is φ = 3807736128000.

The previous prime is 13120120210063. The next prime is 13120120210163. The reversal of 13120120210122 is 22101202102131.

13120120210122 is a `hidden beast` number, since 1 + 312 + 0 + 1 + 20 + 210 + 122 = 666.

13120120210122 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 13120120210095 and 13120120210104.

It is an unprimeable number.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 1637759097 + ... + 1637767107.

It is an arithmetic number, because the mean of its divisors is an integer number (168901452720).

Almost surely, 213120120210122 is an apocalyptic number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13120120210122, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (16214539461120).

13120120210122 is an abundant number, since it is smaller than the sum of its proper divisors (19308958712118).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13120120210122 is a wasteful number, since it uses less digits than its factorization.

13120120210122 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14649 (or 14646 counting only the distinct ones).

The product of its (nonzero) digits is 96, while the sum is 18.

Adding to 13120120210122 its reverse (22101202102131), we get a palindrome (35221322312253).

The spelling of 13120120210122 in words is "thirteen trillion, one hundred twenty billion, one hundred twenty million, two hundred ten thousand, one hundred twenty-two".