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1312012024004 = 2211227131358833
BaseRepresentation
bin10011000101111010000…
…000101011100011000100
311122102112101002111102002
4103011322000223203010
5132444000034232004
62442421403004432
7163534611124463
oct23057200534304
94572471074362
101312012024004
1146646a646660
1219233a209718
13969508abb56
1447704a169da
15241dd76d61e
hex1317a02b8c4

1312012024004 has 24 divisors (see below), whose sum is σ = 2515784388768. Its totient is φ = 593741920640.

The previous prime is 1312012024003. The next prime is 1312012024013. The reversal of 1312012024004 is 4004202102131.

It is a super-2 number, since 2×13120120240042 (a number of 25 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (1312012024003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 65669429 + ... + 65689404.

It is an arithmetic number, because the mean of its divisors is an integer number (104824349532).

Almost surely, 21312012024004 is an apocalyptic number.

It is an amenable number.

1312012024004 is a deficient number, since it is larger than the sum of its proper divisors (1203772364764).

1312012024004 is a wasteful number, since it uses less digits than its factorization.

1312012024004 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 131359075 (or 131359073 counting only the distinct ones).

The product of its (nonzero) digits is 384, while the sum is 20.

Adding to 1312012024004 its reverse (4004202102131), we get a palindrome (5316214126135).

The spelling of 1312012024004 in words is "one trillion, three hundred twelve billion, twelve million, twenty-four thousand, four".

Divisors: 1 2 4 11 22 44 227 454 908 2497 4994 9988 131358833 262717666 525435332 1444947163 2889894326 5779788652 29818455091 59636910182 119273820364 328003006001 656006012002 1312012024004