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131201214140000 = 2554191223282311
BaseRepresentation
bin11101110101001110101001…
…110000110100111001100000
3122012112201021012100002201102
4131311032221300310321200
5114144100041304440000
61143013001121453532
736430655252344334
oct3565165160647140
9565481235302642
10131201214140000
1138894138a78704
121286b8111a12a8
1358292b5575414
14245825ba577c4
151027ca0b643d5
hex7753a9c34e60

131201214140000 has 240 divisors, whose sum is σ = 340041822785280. Its totient is φ = 49677526080000.

The previous prime is 131201214139993. The next prime is 131201214140053. The reversal of 131201214140000 is 41412102131.

131201214140000 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 464598845 + ... + 464881155.

It is an arithmetic number, because the mean of its divisors is an integer number (1416840928272).

Almost surely, 2131201214140000 is an apocalyptic number.

131201214140000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131201214140000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (170020911392640).

131201214140000 is an abundant number, since it is smaller than the sum of its proper divisors (208840608645280).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131201214140000 is a wasteful number, since it uses less digits than its factorization.

131201214140000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 283583 (or 283560 counting only the distinct ones).

The product of its (nonzero) digits is 192, while the sum is 20.

Adding to 131201214140000 its reverse (41412102131), we get a palindrome (131242626242131).

The spelling of 131201214140000 in words is "one hundred thirty-one trillion, two hundred one billion, two hundred fourteen million, one hundred forty thousand".