Base | Representation |
---|---|
bin | 1011111011101100010011… |
… | …0000011001011011111111 |
3 | 1201110021100111102220201202 |
4 | 2332323010300121123333 |
5 | 3204430012033042143 |
6 | 43523145515530115 |
7 | 2522620036436213 |
oct | 276730460313377 |
9 | 51407314386652 |
10 | 13120131143423 |
11 | 41a9241a97907 |
12 | 157a92945993b |
13 | 7422b909b835 |
14 | 335036948943 |
15 | 17b440de4ab8 |
hex | beec4c196ff |
13120131143423 has 8 divisors (see below), whose sum is σ = 13190563007856. Its totient is φ = 13049724556800.
The previous prime is 13120131143377. The next prime is 13120131143437. The reversal of 13120131143423 is 32434113102131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13120131143423 - 214 = 13120131127039 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13120131143443) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5278133 + ... + 7355198.
It is an arithmetic number, because the mean of its divisors is an integer number (1648820375982).
Almost surely, 213120131143423 is an apocalyptic number.
13120131143423 is a deficient number, since it is larger than the sum of its proper divisors (70431864433).
13120131143423 is a wasteful number, since it uses less digits than its factorization.
13120131143423 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12638905.
The product of its (nonzero) digits is 5184, while the sum is 29.
Adding to 13120131143423 its reverse (32434113102131), we get a palindrome (45554244245554).
The spelling of 13120131143423 in words is "thirteen trillion, one hundred twenty billion, one hundred thirty-one million, one hundred forty-three thousand, four hundred twenty-three".
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