Base | Representation |
---|---|
bin | 11101110101001110110110… |
… | …000101111100110010100001 |
3 | 122012112201210121120212200201 |
4 | 131311032312011330302201 |
5 | 114144101002234111222 |
6 | 1143013033431345201 |
7 | 36430663343560234 |
oct | 3565166605746241 |
9 | 565481717525621 |
10 | 131201421003937 |
11 | 38894234819639 |
12 | 1286b86a522201 |
13 | 5829319393a0b |
14 | 245827b30541b |
15 | 1027cb3dc7427 |
hex | 7753b617cca1 |
131201421003937 has 2 divisors, whose sum is σ = 131201421003938. Its totient is φ = 131201421003936.
The previous prime is 131201421003931. The next prime is 131201421003979. The reversal of 131201421003937 is 739300124102131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 111059645018256 + 20141775985681 = 10538484^2 + 4487959^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131201421003937 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 131201421003896 and 131201421003905.
It is not a weakly prime, because it can be changed into another prime (131201421003931) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65600710501968 + 65600710501969.
It is an arithmetic number, because the mean of its divisors is an integer number (65600710501969).
Almost surely, 2131201421003937 is an apocalyptic number.
It is an amenable number.
131201421003937 is a deficient number, since it is larger than the sum of its proper divisors (1).
131201421003937 is an equidigital number, since it uses as much as digits as its factorization.
131201421003937 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 27216, while the sum is 37.
The spelling of 131201421003937 in words is "one hundred thirty-one trillion, two hundred one billion, four hundred twenty-one million, three thousand, nine hundred thirty-seven".
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