Base | Representation |
---|---|
bin | 11101110101001110110110… |
… | …000111011001101110101001 |
3 | 122012112201210122022012212222 |
4 | 131311032312013121232221 |
5 | 114144101002333301432 |
6 | 1143013033443443425 |
7 | 36430663350034133 |
oct | 3565166607315651 |
9 | 565481718265788 |
10 | 131201421384617 |
11 | 38894234a59651 |
12 | 1286b86a686575 |
13 | 582931949807c |
14 | 245827b3a4053 |
15 | 1027cb3e50112 |
hex | 7753b61d9ba9 |
131201421384617 has 2 divisors, whose sum is σ = 131201421384618. Its totient is φ = 131201421384616.
The previous prime is 131201421384587. The next prime is 131201421384643. The reversal of 131201421384617 is 716483124102131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 71643714276121 + 59557707108496 = 8464261^2 + 7717364^2 .
It is a cyclic number.
It is not a de Polignac number, because 131201421384617 - 228 = 131201152949161 is a prime.
It is not a weakly prime, because it can be changed into another prime (131201421354617) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65600710692308 + 65600710692309.
It is an arithmetic number, because the mean of its divisors is an integer number (65600710692309).
Almost surely, 2131201421384617 is an apocalyptic number.
It is an amenable number.
131201421384617 is a deficient number, since it is larger than the sum of its proper divisors (1).
131201421384617 is an equidigital number, since it uses as much as digits as its factorization.
131201421384617 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 193536, while the sum is 44.
Adding to 131201421384617 its reverse (716483124102131), we get a palindrome (847684545486748).
The spelling of 131201421384617 in words is "one hundred thirty-one trillion, two hundred one billion, four hundred twenty-one million, three hundred eighty-four thousand, six hundred seventeen".
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