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1312014433241 is a prime number
BaseRepresentation
bin10011000101111010001…
…001110111101111011001
311122102112112121220021002
4103011322021313233121
5132444001143330431
62442421530354345
7163534640450501
oct23057211675731
94572475556232
101312014433241
11466470a41766
1219233ab8b9b5
1396951243635
1447705082a01
15241dda973cb
hex1317a277bd9

1312014433241 has 2 divisors, whose sum is σ = 1312014433242. Its totient is φ = 1312014433240.

The previous prime is 1312014433157. The next prime is 1312014433277. The reversal of 1312014433241 is 1423344102131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1066667577616 + 245346855625 = 1032796^2 + 495325^2 .

It is a cyclic number.

It is not a de Polignac number, because 1312014433241 - 222 = 1312010238937 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (1312014433291) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656007216620 + 656007216621.

It is an arithmetic number, because the mean of its divisors is an integer number (656007216621).

Almost surely, 21312014433241 is an apocalyptic number.

It is an amenable number.

1312014433241 is a deficient number, since it is larger than the sum of its proper divisors (1).

1312014433241 is an equidigital number, since it uses as much as digits as its factorization.

1312014433241 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 1312014433241 its reverse (1423344102131), we get a palindrome (2735358535372).

The spelling of 1312014433241 in words is "one trillion, three hundred twelve billion, fourteen million, four hundred thirty-three thousand, two hundred forty-one".