13120204104401 has 2 divisors, whose sum is σ = 13120204104402. Its totient is φ = 13120204104400.

The previous prime is 13120204104389. The next prime is 13120204104443. The reversal of 13120204104401 is 10440140202131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11477026226176 + 1643177878225 = 3387776^2 + 1281865^2 .

It is a cyclic number.

It is not a de Polignac number, because 13120204104401 - 2³⁰ = 13119130362577 is a prime.

It is a super-2 number, since 2×13120204104401² (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13120204103401) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6560102052200 + 6560102052201.

It is an arithmetic number, because the mean of its divisors is an integer number (6560102052201).

Almost surely, 2^{13120204104401} is an apocalyptic number.

It is an amenable number.

13120204104401 is a deficient number, since it is larger than the sum of its proper divisors (1).

13120204104401 is an equidigital number, since it uses as much as digits as its factorization.

13120204104401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 13120204104401 its reverse (10440140202131), we get a palindrome (23560344306532).

The spelling of 13120204104401 in words is "thirteen trillion, one hundred twenty billion, two hundred four million, one hundred four thousand, four hundred one".