Base | Representation |
---|---|
bin | 10011000101111010100… |
… | …110101111001010000001 |
3 | 11122102120001212100020221 |
4 | 103011322212233022001 |
5 | 132444010113002012 |
6 | 2442422400503041 |
7 | 163535061664663 |
oct | 23057246571201 |
9 | 4572501770227 |
10 | 1312022000257 |
11 | 46647523a9a1 |
12 | 19234161aa81 |
13 | 96952992967 |
14 | 47706092533 |
15 | 241de58e507 |
hex | 1317a9af281 |
1312022000257 has 32 divisors (see below), whose sum is σ = 1448948390400. Its totient is φ = 1186980873984.
The previous prime is 1312022000243. The next prime is 1312022000299. The reversal of 1312022000257 is 7520002202131.
It is not a de Polignac number, because 1312022000257 - 27 = 1312022000129 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1312022000207) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 15044344 + ... + 15131302.
It is an arithmetic number, because the mean of its divisors is an integer number (45279637200).
Almost surely, 21312022000257 is an apocalyptic number.
1312022000257 is a gapful number since it is divisible by the number (17) formed by its first and last digit.
It is an amenable number.
1312022000257 is a deficient number, since it is larger than the sum of its proper divisors (136926390143).
1312022000257 is an frugal number, since it uses more digits than its factorization.
1312022000257 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 87130 (or 87096 counting only the distinct ones).
The product of its (nonzero) digits is 1680, while the sum is 25.
Adding to 1312022000257 its reverse (7520002202131), we get a palindrome (8832024202388).
The spelling of 1312022000257 in words is "one trillion, three hundred twelve billion, twenty-two million, two hundred fifty-seven", and thus it is an aban number.
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