Base | Representation |
---|---|
bin | 10011000101111010101… |
… | …010100011011110111011 |
3 | 11122102120010202012001012 |
4 | 103011322222203132323 |
5 | 132444010342013034 |
6 | 2442422434144135 |
7 | 163535103333443 |
oct | 23057252433673 |
9 | 4572503665035 |
10 | 1312023001019 |
11 | 466475863875 |
12 | 192341a2204b |
13 | 96952c53323 |
14 | 47706273123 |
15 | 241de6dacce |
hex | 1317aaa37bb |
1312023001019 has 2 divisors, whose sum is σ = 1312023001020. Its totient is φ = 1312023001018.
The previous prime is 1312023000991. The next prime is 1312023001027. The reversal of 1312023001019 is 9101003202131.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1312023001019 is a prime.
It is a super-2 number, since 2×13120230010192 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1312023000985 and 1312023001003.
It is not a weakly prime, because it can be changed into another prime (1312023001519) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656011500509 + 656011500510.
It is an arithmetic number, because the mean of its divisors is an integer number (656011500510).
Almost surely, 21312023001019 is an apocalyptic number.
1312023001019 is a deficient number, since it is larger than the sum of its proper divisors (1).
1312023001019 is an equidigital number, since it uses as much as digits as its factorization.
1312023001019 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 23.
The spelling of 1312023001019 in words is "one trillion, three hundred twelve billion, twenty-three million, one thousand, nineteen".
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