Base | Representation |
---|---|
bin | 11101110101001111101100… |
… | …011001100011100001111110 |
3 | 122012112211011010000000101122 |
4 | 131311033230121203201332 |
5 | 114144104334010104042 |
6 | 1143013304055510542 |
7 | 36431025046065032 |
oct | 3565175431434176 |
9 | 565484133000348 |
10 | 131202332113022 |
11 | 38894662049355 |
12 | 1286ba83688452 |
13 | 5829433079a11 |
14 | 24583263141c2 |
15 | 1027d18d9a7d2 |
hex | 7753ec66387e |
131202332113022 has 4 divisors (see below), whose sum is σ = 196803498169536. Its totient is φ = 65601166056510.
The previous prime is 131202332113007. The next prime is 131202332113037. The reversal of 131202332113022 is 220311233202131.
It is a semiprime because it is the product of two primes.
It is an interprime number because it is at equal distance from previous prime (131202332113007) and next prime (131202332113037).
It is a junction number, because it is equal to n+sod(n) for n = 131202332112982 and 131202332113000.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32800583028254 + ... + 32800583028257.
It is an arithmetic number, because the mean of its divisors is an integer number (49200874542384).
Almost surely, 2131202332113022 is an apocalyptic number.
131202332113022 is a deficient number, since it is larger than the sum of its proper divisors (65601166056514).
131202332113022 is an equidigital number, since it uses as much as digits as its factorization.
131202332113022 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 65601166056513.
The product of its (nonzero) digits is 2592, while the sum is 26.
Adding to 131202332113022 its reverse (220311233202131), we get a palindrome (351513565315153).
The spelling of 131202332113022 in words is "one hundred thirty-one trillion, two hundred two billion, three hundred thirty-two million, one hundred thirteen thousand, twenty-two".
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