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1312023321353 is a prime number
BaseRepresentation
bin10011000101111010101…
…011110001101100001001
311122102120011100110110102
4103011322223301230021
5132444010432240403
62442422445055145
7163535106136403
oct23057253615411
94572504313412
101312023321353
11466475a62508
12192341b574b5
1396953036084
1447706317b73
15241de750b88
hex1317aaf1b09

1312023321353 has 2 divisors, whose sum is σ = 1312023321354. Its totient is φ = 1312023321352.

The previous prime is 1312023321269. The next prime is 1312023321391. The reversal of 1312023321353 is 3531233202131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1220488029049 + 91535292304 = 1104757^2 + 302548^2 .

It is a cyclic number.

It is not a de Polignac number, because 1312023321353 - 222 = 1312019127049 is a prime.

It is not a weakly prime, because it can be changed into another prime (1312023321253) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656011660676 + 656011660677.

It is an arithmetic number, because the mean of its divisors is an integer number (656011660677).

Almost surely, 21312023321353 is an apocalyptic number.

It is an amenable number.

1312023321353 is a deficient number, since it is larger than the sum of its proper divisors (1).

1312023321353 is an equidigital number, since it uses as much as digits as its factorization.

1312023321353 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9720, while the sum is 29.

Adding to 1312023321353 its reverse (3531233202131), we get a palindrome (4843256523484).

The spelling of 1312023321353 in words is "one trillion, three hundred twelve billion, twenty-three million, three hundred twenty-one thousand, three hundred fifty-three".