Base | Representation |
---|---|
bin | 10011000101111010101… |
… | …100000111011010100101 |
3 | 11122102120011111222112021 |
4 | 103011322230013122211 |
5 | 132444010443112331 |
6 | 2442422451023141 |
7 | 163535106660010 |
oct | 23057254073245 |
9 | 4572504458467 |
10 | 1312023410341 |
11 | 466476013356 |
12 | 192341b9aab1 |
13 | 96953067727 |
14 | 4770633c377 |
15 | 241de76c211 |
hex | 1317ab076a5 |
1312023410341 has 4 divisors (see below), whose sum is σ = 1499455326112. Its totient is φ = 1124591494572.
The previous prime is 1312023410309. The next prime is 1312023410371. The reversal of 1312023410341 is 1430143202131.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 1312023410341 - 25 = 1312023410309 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1312023410371) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 93715957875 + ... + 93715957888.
It is an arithmetic number, because the mean of its divisors is an integer number (374863831528).
Almost surely, 21312023410341 is an apocalyptic number.
It is an amenable number.
1312023410341 is a deficient number, since it is larger than the sum of its proper divisors (187431915771).
1312023410341 is an equidigital number, since it uses as much as digits as its factorization.
1312023410341 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 187431915770.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 1312023410341 its reverse (1430143202131), we get a palindrome (2742166612472).
The spelling of 1312023410341 in words is "one trillion, three hundred twelve billion, twenty-three million, four hundred ten thousand, three hundred forty-one".
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