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13120234343257 is a prime number
BaseRepresentation
bin1011111011101100101011…
…1010000100101101011001
31201110021121200122000021211
42332323022322010231121
53204430214442441012
643523204043503121
72522622431556316
oct276731272045531
951407550560254
1013120234343257
1141a9295274428
12157a957b27aa1
13742304592922
1433504652dd0d
1517b449ecc6a7
hexbeecae84b59

13120234343257 has 2 divisors, whose sum is σ = 13120234343258. Its totient is φ = 13120234343256.

The previous prime is 13120234343231. The next prime is 13120234343269. The reversal of 13120234343257 is 75234343202131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10596724178121 + 2523510165136 = 3255261^2 + 1588556^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13120234343257 is a prime.

It is not a weakly prime, because it can be changed into another prime (13120234343057) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6560117171628 + 6560117171629.

It is an arithmetic number, because the mean of its divisors is an integer number (6560117171629).

Almost surely, 213120234343257 is an apocalyptic number.

It is an amenable number.

13120234343257 is a deficient number, since it is larger than the sum of its proper divisors (1).

13120234343257 is an equidigital number, since it uses as much as digits as its factorization.

13120234343257 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 362880, while the sum is 40.

Adding to 13120234343257 its reverse (75234343202131), we get a palindrome (88354577545388).

The spelling of 13120234343257 in words is "thirteen trillion, one hundred twenty billion, two hundred thirty-four million, three hundred forty-three thousand, two hundred fifty-seven".