131202424104133 has 4 divisors (see below), whose sum is σ = 131209880075820. Its totient is φ = 131194968132448.

The previous prime is 131202424104097. The next prime is 131202424104151. The reversal of 131202424104133 is 331401424202131.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1147604415169 + 130054819688964 = 1071263^2 + 11404158^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131202424104133 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131202424104095 and 131202424104104.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131202424144133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3727959448 + ... + 3727994641.

It is an arithmetic number, because the mean of its divisors is an integer number (32802470018955).

Almost surely, 2^{131202424104133} is an apocalyptic number.

It is an amenable number.

131202424104133 is a deficient number, since it is larger than the sum of its proper divisors (7455971687).

131202424104133 is an equidigital number, since it uses as much as digits as its factorization.

131202424104133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7455971686.

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 131202424104133 its reverse (331401424202131), we get a palindrome (462603848306264).

The spelling of 131202424104133 in words is "one hundred thirty-one trillion, two hundred two billion, four hundred twenty-four million, one hundred four thousand, one hundred thirty-three".