Base | Representation |
---|---|
bin | 1011111011101100101101… |
… | …1111101011011011110001 |
3 | 1201110021122101011211211212 |
4 | 2332323023133223123301 |
5 | 3204430230003414301 |
6 | 43523205035045505 |
7 | 2522622611424554 |
oct | 276731337533361 |
9 | 51407571154755 |
10 | 13120244201201 |
11 | 41a929a897895 |
12 | 157a95b2a0895 |
13 | 742306634927 |
14 | 33504797869b |
15 | 17b44acc84bb |
hex | beecb7eb6f1 |
13120244201201 has 2 divisors, whose sum is σ = 13120244201202. Its totient is φ = 13120244201200.
The previous prime is 13120244201191. The next prime is 13120244201213. The reversal of 13120244201201 is 10210244202131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12246535245025 + 873708956176 = 3499505^2 + 934724^2 .
It is a cyclic number.
It is not a de Polignac number, because 13120244201201 - 218 = 13120243939057 is a prime.
It is not a weakly prime, because it can be changed into another prime (13120244201401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6560122100600 + 6560122100601.
It is an arithmetic number, because the mean of its divisors is an integer number (6560122100601).
Almost surely, 213120244201201 is an apocalyptic number.
It is an amenable number.
13120244201201 is a deficient number, since it is larger than the sum of its proper divisors (1).
13120244201201 is an equidigital number, since it uses as much as digits as its factorization.
13120244201201 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 768, while the sum is 23.
Adding to 13120244201201 its reverse (10210244202131), we get a palindrome (23330488403332).
The spelling of 13120244201201 in words is "thirteen trillion, one hundred twenty billion, two hundred forty-four million, two hundred one thousand, two hundred one".
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