131202540531540 has 384 divisors, whose sum is σ = 431196752609280. Its totient is φ = 33052813415424.

The previous prime is 131202540531497. The next prime is 131202540531571. The reversal of 131202540531540 is 45135045202131.

131202540531540 is a `hidden beast` number, since 1 + 3 + 1 + 2 + 0 + 25 + 40 + 53 + 1 + 540 = 666.

It is a Harshad number since it is a multiple of its sum of digits (36).

It is a junction number, because it is equal to n+sod(n) for n = 131202540531495 and 131202540531504.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 3703862269 + ... + 3703897691.

It is an arithmetic number, because the mean of its divisors is an integer number (1122908209920).

Almost surely, 2^{131202540531540} is an apocalyptic number.

131202540531540 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131202540531540, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (215598376304640).

131202540531540 is an abundant number, since it is smaller than the sum of its proper divisors (299994212077740).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131202540531540 is a wasteful number, since it uses less digits than its factorization.

131202540531540 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 39140 (or 39132 counting only the distinct ones).

The product of its (nonzero) digits is 72000, while the sum is 36.

Adding to 131202540531540 its reverse (45135045202131), we get a palindrome (176337585733671).

The spelling of 131202540531540 in words is "one hundred thirty-one trillion, two hundred two billion, five hundred forty million, five hundred thirty-one thousand, five hundred forty".