Base | Representation |
---|---|
bin | 111101000110001010… |
… | …0100110100110100001 |
3 | 110112122210000200001002 |
4 | 1322030110212212201 |
5 | 4122201011330423 |
6 | 140135100321345 |
7 | 12323224024604 |
oct | 1721424464641 |
9 | 415583020032 |
10 | 131203230113 |
11 | 5070889178a |
12 | 21517843255 |
13 | c4ac25a307 |
14 | 64c91da33b |
15 | 362d7db228 |
hex | 1e8c5269a1 |
131203230113 has 2 divisors, whose sum is σ = 131203230114. Its totient is φ = 131203230112.
The previous prime is 131203230101. The next prime is 131203230121. The reversal of 131203230113 is 311032302131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 77845464064 + 53357766049 = 279008^2 + 230993^2 .
It is a cyclic number.
It is not a de Polignac number, because 131203230113 - 210 = 131203229089 is a prime.
It is not a weakly prime, because it can be changed into another prime (131203230143) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65601615056 + 65601615057.
It is an arithmetic number, because the mean of its divisors is an integer number (65601615057).
Almost surely, 2131203230113 is an apocalyptic number.
It is an amenable number.
131203230113 is a deficient number, since it is larger than the sum of its proper divisors (1).
131203230113 is an equidigital number, since it uses as much as digits as its factorization.
131203230113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 324, while the sum is 20.
Adding to 131203230113 its reverse (311032302131), we get a palindrome (442235532244).
The spelling of 131203230113 in words is "one hundred thirty-one billion, two hundred three million, two hundred thirty thousand, one hundred thirteen".
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