Base | Representation |
---|---|
bin | 1011111011101101000101… |
… | …0110000011111010010000 |
3 | 1201110021220012211222111212 |
4 | 2332323101112003322100 |
5 | 3204430430114441222 |
6 | 43523222502355252 |
7 | 2522625212551301 |
oct | 276732126037220 |
9 | 51407805758455 |
10 | 13120342343312 |
11 | 41a934022a476 |
12 | 157a98812bb28 |
13 | 742320a77899 |
14 | 335056a047a8 |
15 | 17b4547126e2 |
hex | beed1583e90 |
13120342343312 has 40 divisors (see below), whose sum is σ = 25472295710400. Its totient is φ = 6546853994112.
The previous prime is 13120342343281. The next prime is 13120342343341. The reversal of 13120342343312 is 21334324302131.
It is a super-2 number, since 2×131203423433122 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 28691114 + ... + 29144822.
It is an arithmetic number, because the mean of its divisors is an integer number (636807392760).
Almost surely, 213120342343312 is an apocalyptic number.
It is an amenable number.
13120342343312 is a deficient number, since it is larger than the sum of its proper divisors (12351953367088).
13120342343312 is a wasteful number, since it uses less digits than its factorization.
13120342343312 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 457383 (or 457377 counting only the distinct ones).
The product of its (nonzero) digits is 31104, while the sum is 32.
Adding to 13120342343312 its reverse (21334324302131), we get a palindrome (34454666645443).
The spelling of 13120342343312 in words is "thirteen trillion, one hundred twenty billion, three hundred forty-two million, three hundred forty-three thousand, three hundred twelve".
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