1312040113 has 2 divisors, whose sum is σ = 1312040114. Its totient is φ = 1312040112.

The previous prime is 1312040101. The next prime is 1312040141. The reversal of 1312040113 is 3110402131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1242351009 + 69689104 = 35247^2 + 8348^2 .

It is a cyclic number.

It is not a de Polignac number, because 1312040113 - 2¹⁷ = 1311909041 is a prime.

It is not a weakly prime, because it can be changed into another prime (1312040143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656020056 + 656020057.

It is an arithmetic number, because the mean of its divisors is an integer number (656020057).

Almost surely, 2^1312040113 is an apocalyptic number.

It is an amenable number.

1312040113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1312040113 is an equidigital number, since it uses as much as digits as its factorization.

1312040113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 16.

The square root of 1312040113 is about 36222.0942657931. The cubic root of 1312040113 is about 1094.7518916893.

Adding to 1312040113 its reverse (3110402131), we get a palindrome (4422442244).

The spelling of 1312040113 in words is "one billion, three hundred twelve million, forty thousand, one hundred thirteen".