Base | Representation |
---|---|
bin | 10011000101111011101… |
… | …100001011001101101001 |
3 | 11122102121100010010212210 |
4 | 103011323230023031221 |
5 | 132444024242444423 |
6 | 2442424250555333 |
7 | 163535402500353 |
oct | 23057354131551 |
9 | 4572540103783 |
10 | 1312040203113 |
11 | 466484542a82 |
12 | 192347738b49 |
13 | 96956697093 |
14 | 477086700d3 |
15 | 241e0e87b93 |
hex | 1317bb0b369 |
1312040203113 has 32 divisors (see below), whose sum is σ = 1760572800000. Its totient is φ = 869124759552.
The previous prime is 1312040203087. The next prime is 1312040203169. The reversal of 1312040203113 is 3113020402131.
It is not a de Polignac number, because 1312040203113 - 214 = 1312040186729 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1312040203113.
It is not an unprimeable number, because it can be changed into a prime (1312040303113) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 390602728 + ... + 390606086.
It is an arithmetic number, because the mean of its divisors is an integer number (55017900000).
Almost surely, 21312040203113 is an apocalyptic number.
It is an amenable number.
1312040203113 is a deficient number, since it is larger than the sum of its proper divisors (448532596887).
1312040203113 is a wasteful number, since it uses less digits than its factorization.
1312040203113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4929.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 1312040203113 its reverse (3113020402131), we get a palindrome (4425060605244).
The spelling of 1312040203113 in words is "one trillion, three hundred twelve billion, forty million, two hundred three thousand, one hundred thirteen".
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