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1312044034140 = 2232572175384859
BaseRepresentation
bin10011000101111011111…
…010110010100001011100
311122102121121022210001200
4103011323322302201130
5132444031233043030
62442424505035500
7163535450164500
oct23057372624134
94572547283050
101312044034140
1146648671a314
12192348a85b90
1396957408a68
1447708d8a300
15241e1492d60
hex1317beb285c

1312044034140 has 216 divisors, whose sum is σ = 4632336661680. Its totient is φ = 299721171456.

The previous prime is 1312044034109. The next prime is 1312044034157. The reversal of 1312044034140 is 414304402131.

1312044034140 is a `hidden beast` number, since 1 + 3 + 1 + 204 + 40 + 3 + 414 + 0 = 666.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 15419031 + ... + 15503889.

Almost surely, 21312044034140 is an apocalyptic number.

1312044034140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1312044034140, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2316168330840).

1312044034140 is an abundant number, since it is smaller than the sum of its proper divisors (3320292627540).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1312044034140 is a wasteful number, since it uses less digits than its factorization.

1312044034140 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 86641 (or 86629 counting only the distinct ones).

The product of its (nonzero) digits is 4608, while the sum is 27.

Adding to 1312044034140 its reverse (414304402131), we get a palindrome (1726348436271).

The spelling of 1312044034140 in words is "one trillion, three hundred twelve billion, forty-four million, thirty-four thousand, one hundred forty".