1312054000121 has 2 divisors, whose sum is σ = 1312054000122. Its totient is φ = 1312054000120.

The previous prime is 1312054000111. The next prime is 1312054000217. The reversal of 1312054000121 is 1210004502131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1310303749225 + 1750250896 = 1144685^2 + 41836^2 .

It is a cyclic number.

It is not a de Polignac number, because 1312054000121 - 2¹⁸ = 1312053737977 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1312054000093 and 1312054000102.

It is not a weakly prime, because it can be changed into another prime (1312054000111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656027000060 + 656027000061.

It is an arithmetic number, because the mean of its divisors is an integer number (656027000061).

Almost surely, 2^{1312054000121} is an apocalyptic number.

It is an amenable number.

1312054000121 is a deficient number, since it is larger than the sum of its proper divisors (1).

1312054000121 is an equidigital number, since it uses as much as digits as its factorization.

1312054000121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 240, while the sum is 20.

Adding to 1312054000121 its reverse (1210004502131), we get a palindrome (2522058502252).

The spelling of 1312054000121 in words is "one trillion, three hundred twelve billion, fifty-four million, one hundred twenty-one", and thus it is an aban number.