13121001131113 has 2 divisors, whose sum is σ = 13121001131114. Its totient is φ = 13121001131112.

The previous prime is 13121001131087. The next prime is 13121001131129. The reversal of 13121001131113 is 31113110012131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12127646055529 + 993355075584 = 3482477^2 + 996672^2 .

It is a cyclic number.

It is not a de Polignac number, because 13121001131113 - 2²⁹ = 13120464260201 is a prime.

It is not a weakly prime, because it can be changed into another prime (13121002131113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6560500565556 + 6560500565557.

It is an arithmetic number, because the mean of its divisors is an integer number (6560500565557).

Almost surely, 2^{13121001131113} is an apocalyptic number.

It is an amenable number.

13121001131113 is a deficient number, since it is larger than the sum of its proper divisors (1).

13121001131113 is an equidigital number, since it uses as much as digits as its factorization.

13121001131113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 19.

Adding to 13121001131113 its reverse (31113110012131), we get a palindrome (44234111143244).

The spelling of 13121001131113 in words is "thirteen trillion, one hundred twenty-one billion, one million, one hundred thirty-one thousand, one hundred thirteen".