Base | Representation |
---|---|
bin | 10011000101111111010… |
… | …000101101101011011111 |
3 | 11122102202111211212221220 |
4 | 103011333100231223133 |
5 | 132444140112104434 |
6 | 2442434231024423 |
7 | 163540030641165 |
oct | 23057720555337 |
9 | 4572674755856 |
10 | 1312100113119 |
11 | 466505342284 |
12 | 19236380b113 |
13 | 96965c120a3 |
14 | 477125c7235 |
15 | 241e636dd49 |
hex | 1317f42dadf |
1312100113119 has 8 divisors (see below), whose sum is σ = 1751448097152. Its totient is φ = 873742768920.
The previous prime is 1312100113099. The next prime is 1312100113157. The reversal of 1312100113119 is 9113110012131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 1312100113119 - 217 = 1312099982047 is a prime.
It is a super-2 number, since 2×13121001131192 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1312100133119) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 247656867 + ... + 247662164.
It is an arithmetic number, because the mean of its divisors is an integer number (218931012144).
Almost surely, 21312100113119 is an apocalyptic number.
1312100113119 is a deficient number, since it is larger than the sum of its proper divisors (439347984033).
1312100113119 is an equidigital number, since it uses as much as digits as its factorization.
1312100113119 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 495319917.
The product of its (nonzero) digits is 162, while the sum is 24.
The spelling of 1312100113119 in words is "one trillion, three hundred twelve billion, one hundred million, one hundred thirteen thousand, one hundred nineteen".
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