Search a number
-
+
13121002001232 = 24323143103769863
BaseRepresentation
bin1011111011101111100010…
…1010011101001101010000
31201110100121012010002001200
42332323320222131031100
53204433303003014412
643523412145231200
72522650442551236
oct276737052351520
951410535102050
1013121002001232
1141a9649625204
12157ab31032500
137423c7630808
143350ba47a956
1517b4925b69dc
hexbeef8a9d350

13121002001232 has 480 divisors, whose sum is σ = 39259567226880. Its totient is φ = 4083950223360.

The previous prime is 13121002001231. The next prime is 13121002001249. The reversal of 13121002001232 is 23210020012131.

13121002001232 is a `hidden beast` number, since 1 + 312 + 100 + 20 + 0 + 1 + 232 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13121002001231) by changing a digit.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 15203941633 + ... + 15203942495.

It is an arithmetic number, because the mean of its divisors is an integer number (81790765056).

Almost surely, 213121002001232 is an apocalyptic number.

13121002001232 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13121002001232, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (19629783613440).

13121002001232 is an abundant number, since it is smaller than the sum of its proper divisors (26138565225648).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13121002001232 is a wasteful number, since it uses less digits than its factorization.

13121002001232 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1823 (or 1814 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

Adding to 13121002001232 its reverse (23210020012131), we get a palindrome (36331022013363).

The spelling of 13121002001232 in words is "thirteen trillion, one hundred twenty-one billion, two million, one thousand, two hundred thirty-two".