Base | Representation |
---|---|
bin | 11101110101010110111101… |
… | …010111111111110101101011 |
3 | 122012120120021202221201122012 |
4 | 131311112331113333311223 |
5 | 114144221323034010443 |
6 | 1143021034130150135 |
7 | 36431422262342564 |
oct | 3565267527776553 |
9 | 565516252851565 |
10 | 131210133110123 |
11 | 388979a55549a1 |
12 | 128714a012234b |
13 | 582a0a72c4632 |
14 | 24588663b916b |
15 | 1028123b87118 |
hex | 7755bd5ffd6b |
131210133110123 has 2 divisors, whose sum is σ = 131210133110124. Its totient is φ = 131210133110122.
The previous prime is 131210133110099. The next prime is 131210133110167. The reversal of 131210133110123 is 321011331012131.
It is a weak prime.
It is an emirp because it is prime and its reverse (321011331012131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 131210133110123 - 218 = 131210132847979 is a prime.
It is not a weakly prime, because it can be changed into another prime (131210133119123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65605066555061 + 65605066555062.
It is an arithmetic number, because the mean of its divisors is an integer number (65605066555062).
Almost surely, 2131210133110123 is an apocalyptic number.
131210133110123 is a deficient number, since it is larger than the sum of its proper divisors (1).
131210133110123 is an equidigital number, since it uses as much as digits as its factorization.
131210133110123 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 23.
Adding to 131210133110123 its reverse (321011331012131), we get a palindrome (452221464122254).
The spelling of 131210133110123 in words is "one hundred thirty-one trillion, two hundred ten billion, one hundred thirty-three million, one hundred ten thousand, one hundred twenty-three".
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