Base | Representation |
---|---|
bin | 1011111011101111100111… |
… | …1011011100000100001111 |
3 | 1201110100122200001121202121 |
4 | 2332323321323130010033 |
5 | 3204433323421331343 |
6 | 43523414224233411 |
7 | 2522651121156316 |
oct | 276737173340417 |
9 | 51410580047677 |
10 | 13121023230223 |
11 | 41a965a604927 |
12 | 157ab3816b867 |
13 | 7423cbb5444c |
14 | 3350bd20527d |
15 | 17b4943abaed |
hex | beef9edc10f |
13121023230223 has 4 divisors (see below), whose sum is σ = 13121064513160. Its totient is φ = 13120981947288.
The previous prime is 13121023230221. The next prime is 13121023230229. The reversal of 13121023230223 is 32203232012131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13121023230223 - 21 = 13121023230221 is a prime.
It is a super-2 number, since 2×131210232302232 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13121023230221) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20160993 + ... + 20801626.
It is an arithmetic number, because the mean of its divisors is an integer number (3280266128290).
Almost surely, 213121023230223 is an apocalyptic number.
13121023230223 is a deficient number, since it is larger than the sum of its proper divisors (41282937).
13121023230223 is an equidigital number, since it uses as much as digits as its factorization.
13121023230223 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 41282936.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 13121023230223 its reverse (32203232012131), we get a palindrome (45324255242354).
The spelling of 13121023230223 in words is "thirteen trillion, one hundred twenty-one billion, twenty-three million, two hundred thirty thousand, two hundred twenty-three".
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