Base | Representation |
---|---|
bin | 10011000101111111011… |
… | …100111100111011111101 |
3 | 11122102202201212212210221 |
4 | 103011333130330323331 |
5 | 132444141422240331 |
6 | 2442434423501341 |
7 | 163540100132461 |
oct | 23057734747375 |
9 | 4572681785727 |
10 | 1312103321341 |
11 | 4665071336aa |
12 | 1923648b7851 |
13 | 96966796447 |
14 | 47712bc04a1 |
15 | 241e67a4711 |
hex | 1317f73cefd |
1312103321341 has 4 divisors (see below), whose sum is σ = 1324365969312. Its totient is φ = 1299840673372.
The previous prime is 1312103321329. The next prime is 1312103321357. The reversal of 1312103321341 is 1431233012131.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1312103321341 - 213 = 1312103313149 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1312103321381) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6131323825 + ... + 6131324038.
It is an arithmetic number, because the mean of its divisors is an integer number (331091492328).
Almost surely, 21312103321341 is an apocalyptic number.
It is an amenable number.
1312103321341 is a deficient number, since it is larger than the sum of its proper divisors (12262647971).
1312103321341 is a wasteful number, since it uses less digits than its factorization.
1312103321341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12262647970.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 1312103321341 its reverse (1431233012131), we get a palindrome (2743336333472).
The spelling of 1312103321341 in words is "one trillion, three hundred twelve billion, one hundred three million, three hundred twenty-one thousand, three hundred forty-one".
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