Base | Representation |
---|---|
bin | 10011000101111111011… |
… | …111100111100000010111 |
3 | 11122102202210012101011212 |
4 | 103011333133213200113 |
5 | 132444142112114431 |
6 | 2442434450452035 |
7 | 163540106102402 |
oct | 23057737474027 |
9 | 4572683171155 |
10 | 1312104019991 |
11 | 4665075705a6 |
12 | 192364b9401b |
13 | 9696697c44b |
14 | 47712d22d39 |
15 | 241e689172b |
hex | 1317f7e7817 |
1312104019991 has 4 divisors (see below), whose sum is σ = 1312273178712. Its totient is φ = 1311934861272.
The previous prime is 1312104019979. The next prime is 1312104020057. The reversal of 1312104019991 is 1999104012131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1312104019991 - 26 = 1312104019927 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1312104019901) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 84567725 + ... + 84583238.
It is an arithmetic number, because the mean of its divisors is an integer number (328068294678).
Almost surely, 21312104019991 is an apocalyptic number.
1312104019991 is a deficient number, since it is larger than the sum of its proper divisors (169158721).
1312104019991 is an equidigital number, since it uses as much as digits as its factorization.
1312104019991 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 169158720.
The product of its (nonzero) digits is 17496, while the sum is 41.
The spelling of 1312104019991 in words is "one trillion, three hundred twelve billion, one hundred four million, nineteen thousand, nine hundred ninety-one".
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