Base | Representation |
---|---|
bin | 10011000101111111011… |
… | …111100111100000001011 |
3 | 11122102202210012101011102 |
4 | 103011333133213200023 |
5 | 132444142112114404 |
6 | 2442434450452015 |
7 | 163540106102354 |
oct | 23057737474013 |
9 | 4572683171142 |
10 | 1312104019979 |
11 | 466507570595 |
12 | 192364b9400b |
13 | 9696697c43c |
14 | 47712d22d2b |
15 | 241e689171e |
hex | 1317f7e780b |
1312104019979 has 2 divisors, whose sum is σ = 1312104019980. Its totient is φ = 1312104019978.
The previous prime is 1312104019943. The next prime is 1312104020057. The reversal of 1312104019979 is 9799104012131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1312104019979 - 236 = 1243384543243 is a prime.
It is not a weakly prime, because it can be changed into another prime (1312104019879) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656052009989 + 656052009990.
It is an arithmetic number, because the mean of its divisors is an integer number (656052009990).
Almost surely, 21312104019979 is an apocalyptic number.
1312104019979 is a deficient number, since it is larger than the sum of its proper divisors (1).
1312104019979 is an equidigital number, since it uses as much as digits as its factorization.
1312104019979 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 122472, while the sum is 47.
The spelling of 1312104019979 in words is "one trillion, three hundred twelve billion, one hundred four million, nineteen thousand, nine hundred seventy-nine".
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