1312104020031 has 12 divisors (see below), whose sum is σ = 2166012985552. Its totient is φ = 749773725696.

The previous prime is 1312104019979. The next prime is 1312104020057. The reversal of 1312104020031 is 1300204012131.

It is not a de Polignac number, because 1312104020031 - 2²³ = 1312095631423 is a prime.

It is a super-2 number, since 2×1312104020031² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1312104019986 and 1312104020013.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1312104021031) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 10413523906 + ... + 10413524031.

Almost surely, 2^{1312104020031} is an apocalyptic number.

1312104020031 is a deficient number, since it is larger than the sum of its proper divisors (853908965521).

1312104020031 is a wasteful number, since it uses less digits than its factorization.

1312104020031 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20827047950 (or 20827047947 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

Adding to 1312104020031 its reverse (1300204012131), we get a palindrome (2612308032162).

The spelling of 1312104020031 in words is "one trillion, three hundred twelve billion, one hundred four million, twenty thousand, thirty-one".