Base | Representation |
---|---|
bin | 1011111011101111110111… |
… | …0010011100111100101011 |
3 | 1201110100211011220102102112 |
4 | 2332323331302130330223 |
5 | 3204433442010432103 |
6 | 43523424500152535 |
7 | 2522652535441151 |
oct | 276737562347453 |
9 | 51410734812375 |
10 | 13121087983403 |
11 | 41a9693111954 |
12 | 157ab5599874b |
13 | 74240c3a6a3a |
14 | 3350c7a5d3d1 |
15 | 17b499deccd8 |
hex | beefdc9cf2b |
13121087983403 has 2 divisors, whose sum is σ = 13121087983404. Its totient is φ = 13121087983402.
The previous prime is 13121087983337. The next prime is 13121087983477. The reversal of 13121087983403 is 30438978012131.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13121087983403 is a prime.
It is not a weakly prime, because it can be changed into another prime (13121087983103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6560543991701 + 6560543991702.
It is an arithmetic number, because the mean of its divisors is an integer number (6560543991702).
Almost surely, 213121087983403 is an apocalyptic number.
13121087983403 is a deficient number, since it is larger than the sum of its proper divisors (1).
13121087983403 is an equidigital number, since it uses as much as digits as its factorization.
13121087983403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 870912, while the sum is 50.
The spelling of 13121087983403 in words is "thirteen trillion, one hundred twenty-one billion, eighty-seven million, nine hundred eighty-three thousand, four hundred three".
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