Base | Representation |
---|---|
bin | 10011000101111111110… |
… | …111001111100000001011 |
3 | 11122102210012212000120102 |
4 | 103011333313033200023 |
5 | 132444200203310011 |
6 | 2442435231320015 |
7 | 163540212535244 |
oct | 23057767174013 |
9 | 4572705760512 |
10 | 1312110213131 |
11 | 4665100105a3 |
12 | 19236708000b |
13 | 9696803a323 |
14 | 47713a95ccb |
15 | 241e71b673b |
hex | 1317fdcf80b |
1312110213131 has 2 divisors, whose sum is σ = 1312110213132. Its totient is φ = 1312110213130.
The previous prime is 1312110213103. The next prime is 1312110213181. The reversal of 1312110213131 is 1313120112131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1312110213131 - 222 = 1312106018827 is a prime.
It is a super-2 number, since 2×13121102131312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1312110213101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656055106565 + 656055106566.
It is an arithmetic number, because the mean of its divisors is an integer number (656055106566).
Almost surely, 21312110213131 is an apocalyptic number.
1312110213131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1312110213131 is an equidigital number, since it uses as much as digits as its factorization.
1312110213131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108, while the sum is 20.
Adding to 1312110213131 its reverse (1313120112131), we get a palindrome (2625230325262).
The spelling of 1312110213131 in words is "one trillion, three hundred twelve billion, one hundred ten million, two hundred thirteen thousand, one hundred thirty-one".
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