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1312111023283 is a prime number
BaseRepresentation
bin10011000101111111111…
…010010101010010110011
311122102210021101011220001
4103011333322111102303
5132444200410221113
62442435300530431
7163540222451224
oct23057772252263
94572707334801
101312111023283
11466510514245
121923673b0a17
1396968261cc8
1447713c2724b
15241e72c67dd
hex1317fe954b3

1312111023283 has 2 divisors, whose sum is σ = 1312111023284. Its totient is φ = 1312111023282.

The previous prime is 1312111023241. The next prime is 1312111023323. The reversal of 1312111023283 is 3823201112131.

It is a strong prime.

It is an emirp because it is prime and its reverse (3823201112131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1312111023283 - 29 = 1312111022771 is a prime.

It is a super-2 number, since 2×13121110232832 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1312111023383) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656055511641 + 656055511642.

It is an arithmetic number, because the mean of its divisors is an integer number (656055511642).

Almost surely, 21312111023283 is an apocalyptic number.

1312111023283 is a deficient number, since it is larger than the sum of its proper divisors (1).

1312111023283 is an equidigital number, since it uses as much as digits as its factorization.

1312111023283 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1728, while the sum is 28.

The spelling of 1312111023283 in words is "one trillion, three hundred twelve billion, one hundred eleven million, twenty-three thousand, two hundred eighty-three".