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131211210000419 is a prime number
BaseRepresentation
bin11101110101010111111101…
…100100000000100000100011
3122012120200001211022102101222
4131311113331210000200203
5114144231024230003134
61143021333035445255
736431461046635463
oct3565277544004043
9565520054272358
10131211210000419
11388983a841557a
12128717408b682b
13582a219443623
14245892941dba3
1510281884a5a2e
hex7755fd900823

131211210000419 has 2 divisors, whose sum is σ = 131211210000420. Its totient is φ = 131211210000418.

The previous prime is 131211210000413. The next prime is 131211210000467. The reversal of 131211210000419 is 914000012112131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 131211210000419 - 224 = 131211193223203 is a prime.

It is a super-2 number, since 2×1312112100004192 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (131211210000413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65605605000209 + 65605605000210.

It is an arithmetic number, because the mean of its divisors is an integer number (65605605000210).

Almost surely, 2131211210000419 is an apocalyptic number.

131211210000419 is a deficient number, since it is larger than the sum of its proper divisors (1).

131211210000419 is an equidigital number, since it uses as much as digits as its factorization.

131211210000419 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 26.

The spelling of 131211210000419 in words is "one hundred thirty-one trillion, two hundred eleven billion, two hundred ten million, four hundred nineteen", and thus it is an aban number.