Base | Representation |
---|---|
bin | 11101110101010111111101… |
… | …100101001100000110000110 |
3 | 122012120200001211220011002202 |
4 | 131311113331211030012012 |
5 | 114144231024314410042 |
6 | 1143021333050234502 |
7 | 36431461052365223 |
oct | 3565277545140606 |
9 | 565520054804082 |
10 | 131211210310022 |
11 | 388983a8607147 |
12 | 12871740a25a32 |
13 | 582a21952151b |
14 | 24589294a094a |
15 | 1028188517632 |
hex | 7755fd94c186 |
131211210310022 has 4 divisors (see below), whose sum is σ = 196816815465036. Its totient is φ = 65605605155010.
The previous prime is 131211210310007. The next prime is 131211210310067. The reversal of 131211210310022 is 220013012112131.
It is a semiprime because it is the product of two primes.
It is a super-2 number, since 2×1312112103100222 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 131211210309976 and 131211210310003.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32802802577504 + ... + 32802802577507.
It is an arithmetic number, because the mean of its divisors is an integer number (49204203866259).
Almost surely, 2131211210310022 is an apocalyptic number.
131211210310022 is a deficient number, since it is larger than the sum of its proper divisors (65605605155014).
131211210310022 is an equidigital number, since it uses as much as digits as its factorization.
131211210310022 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 65605605155013.
The product of its (nonzero) digits is 144, while the sum is 20.
Adding to 131211210310022 its reverse (220013012112131), we get a palindrome (351224222422153).
The spelling of 131211210310022 in words is "one hundred thirty-one trillion, two hundred eleven billion, two hundred ten million, three hundred ten thousand, twenty-two".
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