Base | Representation |
---|---|
bin | 11101110101010111111101… |
… | …101000010001111100010011 |
3 | 122012120200001220102022201212 |
4 | 131311113331220101330103 |
5 | 114144231030021323103 |
6 | 1143021333115450335 |
7 | 36431461062311651 |
oct | 3565277550217423 |
9 | 565520056368655 |
10 | 131211211120403 |
11 | 388983a900aa87 |
12 | 128717411569ab |
13 | 582a21974633b |
14 | 2458929631dd1 |
15 | 10281886277d8 |
hex | 7755fda11f13 |
131211211120403 has 2 divisors, whose sum is σ = 131211211120404. Its totient is φ = 131211211120402.
The previous prime is 131211211120219. The next prime is 131211211120417. The reversal of 131211211120403 is 304021112112131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131211211120403 - 28 = 131211211120147 is a prime.
It is not a weakly prime, because it can be changed into another prime (131211211120433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65605605560201 + 65605605560202.
It is an arithmetic number, because the mean of its divisors is an integer number (65605605560202).
Almost surely, 2131211211120403 is an apocalyptic number.
131211211120403 is a deficient number, since it is larger than the sum of its proper divisors (1).
131211211120403 is an equidigital number, since it uses as much as digits as its factorization.
131211211120403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 288, while the sum is 23.
Adding to 131211211120403 its reverse (304021112112131), we get a palindrome (435232323232534).
The spelling of 131211211120403 in words is "one hundred thirty-one trillion, two hundred eleven billion, two hundred eleven million, one hundred twenty thousand, four hundred three".
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