Base | Representation |
---|---|
bin | 11101110101010111111110… |
… | …010011000011010000000001 |
3 | 122012120200002200111221201122 |
4 | 131311113332103003100001 |
5 | 114144231040404114132 |
6 | 1143021334200042025 |
7 | 36431461256520023 |
oct | 3565277623032001 |
9 | 565520080457648 |
10 | 131211222332417 |
11 | 38898404378807 |
12 | 12871744a63315 |
13 | 582a21bb70776 |
14 | 245892ad10013 |
15 | 10281895de912 |
hex | 7755fe4c3401 |
131211222332417 has 2 divisors, whose sum is σ = 131211222332418. Its totient is φ = 131211222332416.
The previous prime is 131211222332413. The next prime is 131211222332479. The reversal of 131211222332417 is 714233222112131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 90470078003776 + 40741144328641 = 9511576^2 + 6382879^2 .
It is a cyclic number.
It is not a de Polignac number, because 131211222332417 - 22 = 131211222332413 is a prime.
It is not a weakly prime, because it can be changed into another prime (131211222332413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65605611166208 + 65605611166209.
It is an arithmetic number, because the mean of its divisors is an integer number (65605611166209).
Almost surely, 2131211222332417 is an apocalyptic number.
It is an amenable number.
131211222332417 is a deficient number, since it is larger than the sum of its proper divisors (1).
131211222332417 is an equidigital number, since it uses as much as digits as its factorization.
131211222332417 is an evil number, because the sum of its binary digits is even.
The product of its digits is 24192, while the sum is 35.
Adding to 131211222332417 its reverse (714233222112131), we get a palindrome (845444444444548).
The spelling of 131211222332417 in words is "one hundred thirty-one trillion, two hundred eleven billion, two hundred twenty-two million, three hundred thirty-two thousand, four hundred seventeen".
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