13121122320133 has 4 divisors (see below), whose sum is σ = 13121139172320. Its totient is φ = 13121105467948.

The previous prime is 13121122320107. The next prime is 13121122320143. The reversal of 13121122320133 is 33102322112131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13121122320133 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13121122320098 and 13121122320107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13121122320143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7198585 + ... + 8835262.

It is an arithmetic number, because the mean of its divisors is an integer number (3280284793080).

Almost surely, 2^{13121122320133} is an apocalyptic number.

It is an amenable number.

13121122320133 is a deficient number, since it is larger than the sum of its proper divisors (16852187).

13121122320133 is an equidigital number, since it uses as much as digits as its factorization.

13121122320133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 16852186.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 13121122320133 its reverse (33102322112131), we get a palindrome (46223444432264).

The spelling of 13121122320133 in words is "thirteen trillion, one hundred twenty-one billion, one hundred twenty-two million, three hundred twenty thousand, one hundred thirty-three".