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13121130000 = 243541139761
BaseRepresentation
bin11000011100001010…
…01000111000010000
31020212102201110120210
430032011020320100
5203333002130000
610005555204120
7643103523216
oct141605107020
936772643523
1013121130000
1156235991a0
1226622a6640
131311503064
148c689acb6
1551bdcc350
hex30e148e10

13121130000 has 200 divisors, whose sum is σ = 46208533536. Its totient is φ = 3180800000.

The previous prime is 13121129977. The next prime is 13121130007. The reversal of 13121130000 is 3112131.

It is a tau number, because it is divible by the number of its divisors (200).

It is a Harshad number since it is a multiple of its sum of digits (12).

It is not an unprimeable number, because it can be changed into a prime (13121130007) by changing a digit.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 310120 + ... + 349880.

Almost surely, 213121130000 is an apocalyptic number.

13121130000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13121130000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (23104266768).

13121130000 is an abundant number, since it is smaller than the sum of its proper divisors (33087403536).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13121130000 is a wasteful number, since it uses less digits than its factorization.

13121130000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 39803 (or 39782 counting only the distinct ones).

The product of its (nonzero) digits is 18, while the sum is 12.

Adding to 13121130000 its reverse (3112131), we get a palindrome (13124242131).

The spelling of 13121130000 in words is "thirteen billion, one hundred twenty-one million, one hundred thirty thousand".