131211300003431 has 4 divisors (see below), whose sum is σ = 132872202535200. Its totient is φ = 129550397471664.

The previous prime is 131211300003313. The next prime is 131211300003439. The reversal of 131211300003431 is 134300003112131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131211300003431 - 2¹⁰ = 131211300002407 is a prime.

It is a super-2 number, since 2×131211300003431² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131211300003397 and 131211300003406.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131211300003439) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 830451265766 + ... + 830451265923.

It is an arithmetic number, because the mean of its divisors is an integer number (33218050633800).

Almost surely, 2^{131211300003431} is an apocalyptic number.

131211300003431 is a deficient number, since it is larger than the sum of its proper divisors (1660902531769).

131211300003431 is an equidigital number, since it uses as much as digits as its factorization.

131211300003431 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1660902531768.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 131211300003431 its reverse (134300003112131), we get a palindrome (265511303115562).

The spelling of 131211300003431 in words is "one hundred thirty-one trillion, two hundred eleven billion, three hundred million, three thousand, four hundred thirty-one".