Base | Representation |
---|---|
bin | 11110100010010100100111… |
… | …111110101001010011000011 |
3 | 122121111221210010111010111012 |
4 | 132202110213332221103003 |
5 | 120100332401244042011 |
6 | 1153344323015511135 |
7 | 40200566163121433 |
oct | 3642244776512303 |
9 | 577457703433435 |
10 | 134300003112131 |
11 | 398793476212aa |
12 | 130902a73884ab |
13 | 59c2588a2bbcc |
14 | 2524224c102c3 |
15 | 107d6b8129a8b |
hex | 7a2527fa94c3 |
134300003112131 has 2 divisors, whose sum is σ = 134300003112132. Its totient is φ = 134300003112130.
The previous prime is 134300003112127. The next prime is 134300003112181. The reversal of 134300003112131 is 131211300003431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 134300003112131 - 22 = 134300003112127 is a prime.
It is a super-2 number, since 2×1343000031121312 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 134300003112097 and 134300003112106.
It is not a weakly prime, because it can be changed into another prime (134300003112181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67150001556065 + 67150001556066.
It is an arithmetic number, because the mean of its divisors is an integer number (67150001556066).
Almost surely, 2134300003112131 is an apocalyptic number.
134300003112131 is a deficient number, since it is larger than the sum of its proper divisors (1).
134300003112131 is an equidigital number, since it uses as much as digits as its factorization.
134300003112131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 134300003112131 its reverse (131211300003431), we get a palindrome (265511303115562).
The spelling of 134300003112131 in words is "one hundred thirty-four trillion, three hundred billion, three million, one hundred twelve thousand, one hundred thirty-one".
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