Base | Representation |
---|---|
bin | 1011111011110000000001… |
… | …0011001101000000111011 |
3 | 1201110100221010012100112022 |
4 | 2332330000103031000323 |
5 | 3204434033302421243 |
6 | 43523433003305055 |
7 | 2522653556561105 |
oct | 276740023150073 |
9 | 51410833170468 |
10 | 13121130123323 |
11 | 41a9704984232 |
12 | 157ab67b1b18b |
13 | 74241803c5c1 |
14 | 3350cd4ac575 |
15 | 17b49d973b68 |
hex | bef004cd03b |
13121130123323 has 2 divisors, whose sum is σ = 13121130123324. Its totient is φ = 13121130123322.
The previous prime is 13121130123293. The next prime is 13121130123341. The reversal of 13121130123323 is 32332103112131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13121130123323 - 216 = 13121130057787 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13121130123292 and 13121130123301.
It is not a weakly prime, because it can be changed into another prime (13121130120323) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6560565061661 + 6560565061662.
It is an arithmetic number, because the mean of its divisors is an integer number (6560565061662).
Almost surely, 213121130123323 is an apocalyptic number.
13121130123323 is a deficient number, since it is larger than the sum of its proper divisors (1).
13121130123323 is an equidigital number, since it uses as much as digits as its factorization.
13121130123323 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1944, while the sum is 26.
Adding to 13121130123323 its reverse (32332103112131), we get a palindrome (45453233235454).
The spelling of 13121130123323 in words is "thirteen trillion, one hundred twenty-one billion, one hundred thirty million, one hundred twenty-three thousand, three hundred twenty-three".
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