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13121132244000 = 2535311293427673
BaseRepresentation
bin1011111011110000000001…
…1011010010110000100000
31201110100221021012002112220
42332330000123102300200
53204434034323302000
643523433120551040
72522653613602614
oct276740033226040
951410837162486
1013121132244000
1141a97060a2560
12157ab68782480
13742418602941
143350cd8a1344
1517b49dc421a0
hexbef006d2c20

13121132244000 has 384 divisors, whose sum is σ = 48509539303680. Its totient is φ = 3071194112000.

The previous prime is 13121132243941. The next prime is 13121132244067. The reversal of 13121132244000 is 44223112131.

It is a super-2 number, since 2×131211322440002 (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (24).

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 2114164 + ... + 5541836.

It is an arithmetic number, because the mean of its divisors is an integer number (126326925270).

Almost surely, 213121132244000 is an apocalyptic number.

13121132244000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13121132244000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (24254769651840).

13121132244000 is an abundant number, since it is smaller than the sum of its proper divisors (35388407059680).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13121132244000 is a wasteful number, since it uses less digits than its factorization.

13121132244000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3427741 (or 3427723 counting only the distinct ones).

The product of its (nonzero) digits is 1152, while the sum is 24.

Adding to 13121132244000 its reverse (44223112131), we get a palindrome (13165355356131).

The spelling of 13121132244000 in words is "thirteen trillion, one hundred twenty-one billion, one hundred thirty-two million, two hundred forty-four thousand".